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bilngan pangkat
[tex]\sf a^m : a^n = a^{m-n}[/tex]
[tex]\sf (a^m)(a^n) = a^{m+n}[/tex]
[tex]\sf (a^m)^n = a^{m+n}[/tex]
Penjelasan dengan langkah-langkah:
[tex]\sf 6). 64^{\frac{2}{3}} - 16^{\frac{1}{4}}+216^{\frac{1}{3}}[/tex]
[tex]\sf = (4^3)^{\frac{2}{3}}- (2^4)^{\frac{1}{4}}+(6^3)^{\frac{1}{3}}[/tex]
[tex]\sf = (4^2)- (2^1)+(6^1) = 16 -2 + 6 =20[/tex]
[tex]\sf 7) \ \dfrac{2^4. 5^{-3}. 9^{-2}}{3^{-5}. 125^{-1}. 8}=[/tex]
= 2⁴. 5⁻³. 9⁻². 3⁵. 125. 8⁻¹
= 2⁴. 5⁻³. (3²)⁻². 3⁵. 5³. (2³)⁻¹
= 2⁴. 5⁻³. 3⁻⁴. 3⁵. 5³. 2⁻³
= 2⁴. 2⁻³. 3⁻⁴. 3⁵. 5⁻³. 5³
= (2)¹. (3)¹. (5)⁰
= (2)(3)(1)
= 6
[answer.2.content]